A) \[3.0\times {{10}^{-19}}/{{m}^{3}}\]
B) \[5\times {{10}^{9}}/{{m}^{3}}\]
C) \[4.5\times {{10}^{22}}/{{m}^{3}}\]
D) \[1.5\times {{10}^{16}}/{{m}^{3}}\]
Correct Answer: B
Solution :
From law of mass-action \[n_{e}^{}n_{h}^{}=n_{i}^{2}\] \[n_{e}^{}=\frac{n_{i}^{2}}{{{n}_{h}}}\] \[n_{h}^{}=4.5\times {{10}^{22}}/{{m}^{3}}\] \[n_{e}^{}=\frac{{{(1.5\times {{10}^{16}})}^{2}}}{4.5\times {{10}^{22}}}\] \[n_{e}^{}=5\times {{10}^{9}}/{{m}^{3}}\]
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