VMMC VMMC Medical Solved Paper-2013

  • question_answer
    An ionic compound made up of atoms A and B has fee arrangement in which atoms A are at the corners and atoms B are at the face-centres. If one of the atoms is missing from the corner, the simplest formula of the compound will be

    A) \[{{A}_{7}}{{B}_{24}}\]

    B) \[{{A}_{2}}{{B}_{3}}\]

    C)  \[{{A}_{3}}{{B}_{7}}\]

    D)  \[{{A}_{3}}{{B}_{10}}\]

    Correct Answer: A

    Solution :

     No. of atoms of A at the corners \[=7\times \frac{1}{8}\] (because one A is missing) =7/8 Contribution of atom B towards unit cell\[=6\times \frac{1}{2}=3\] Ratio of \[A:B=\frac{7}{8}:3=7:24\] Formula is \[{{A}_{7}}{{B}_{24}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner