A) 5 unpaired electrons \[(t_{2g}^{3}e_{g}^{2})\]
B) 1 unpaired electron \[(t_{2g}^{1})\]
C) 3 unpaired electrons \[(t_{2g}^{1}e_{g}^{2})\]
D) All the electrons are paired
Correct Answer: A
Solution :
In \[{{[FeC{{l}_{6}}]}^{3-}},Fe\]is in + 3 oxidation state. Cl is a weak field ligand so the electrons remain unpaired. \[_{26}Fe=[Ar]3{{d}^{6}}4{{s}^{2}};F{{e}^{3+}}=[Ar]3{{d}^{5}}\] (\[5{{e}^{-}},\]unpaired electrons) Therefore, option \[(a)t_{2g}^{3}e_{g}^{2}\]is correct.
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