A) \[N{{I}_{3}},I_{3}^{-}\]
B) \[I_{3}^{-},SO_{3}^{2-}\]
C) \[N{{I}_{3}},SO_{3}^{2-}\]
D) \[I_{3}^{-},NO_{3}^{-}\]
Correct Answer: C
Solution :
\[N{{l}_{3}}\]and \[SO_{3}^{2-}\]are trigonal pyramidal, \[l_{3}^{-}\]is linear and \[NO_{3}^{-}\] is trigonal planar.You need to login to perform this action.
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