A) \[\frac{{{E}_{n}}}{2}\]
B) \[2{{E}_{n}}\]
C) \[4{{E}_{n}}\]
D) \[\frac{{{E}_{n}}}{4}\]
Correct Answer: C
Solution :
The total energy in the \[{{\text{n}}^{\text{th}}}\] orbit is g; /en b \[E=-\frac{m{{z}^{2}}{{e}^{4}}}{8\varepsilon _{0}^{2}{{h}^{2}}}\left( \frac{1}{{{n}^{2}}} \right)\] \[Z=2\] \[E\propto {{Z}^{2}}\] \[{{E}^{2}}\propto 4\] \[E=4{{E}_{n}}\]
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