VMMC VMMC Medical Solved Paper-2013

  • question_answer
    At an instant t, the coordinate of a particles are \[x=a{{t}^{2}},y=b{{t}^{2}}\]and \[z=0.\]The magnitude of velocity of particle at an instant t is

    A) \[t\sqrt{{{a}^{2}}+{{b}^{2}}}\]

    B)  \[\frac{v}{\sqrt{2}}\]

    C)  \[\frac{v}{\sqrt{3}}\]

    D)  \[2t\sqrt{{{a}^{2}}+{{b}^{2}}}\]

    Correct Answer: D

    Solution :

     Here, displacement at an instant? Is \[s=a{{t}^{2}}\hat{i}+b{{t}^{2}}\hat{j}\] \[v=\frac{ds}{dt}=2at\hat{i}+2bt\,\hat{j}\] \[|v|=\sqrt{{{(2at)}^{2}}+{{(2bt)}^{2}}}\] \[=2t\sqrt{{{a}^{2}}+{{b}^{2}}}\]


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