A) 2 unit
B) 4 unit
C) -2 unit
D) -4 unit
Correct Answer: C
Solution :
\[w=F.s\] \[=(2\hat{i}+3\hat{i}+\hat{k})(-2\hat{i}+\hat{J}+\hat{k})\] \[=-4+3-1\] \[=-2\,\text{uni}{{\text{t}}^{\text{2}}}\]
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