VMMC VMMC Medical Solved Paper-2013

  • question_answer
    The optical path difference is defined as \[\Delta x=\frac{2\pi }{\lambda }.\]what are dimensions of optical path difference?

    A) \[{{M}^{0}}{{L}^{-1}}{{T}^{0}}\]

    B)  \[[{{M}^{1}}{{L}^{-1}}{{T}^{0}}]\]

    C)  \[[M{{L}^{0}}{{T}^{2}}]\]

    D)  \[[M{{L}^{-2}}T]\]

    Correct Answer: A

    Solution :

    \[\Delta x=\frac{2\pi }{\lambda }\] \[[\Delta x]=\left[ \frac{2\pi }{\lambda } \right]=\left[ \frac{1}{L} \right]=[{{L}^{-1}}]\] \[=[{{M}^{0}}{{L}^{-1}}{{T}^{0}}]\]


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