A) ACB
B) BAC
C) BCA
D) ABC
Correct Answer: A
Solution :
One map unit or centimorgan is equivalent to 1% recombination between two genes. The frequency of recombination can be used to depict the arrangement of the genes. Recombination frequency between these genes is A-B-9%, A-C = 17% and B-C = 26%. By manipulating the three possibilities of their arrangements A-B-C, A - C-B and B-A-C, it was found that the three gene must be arrangement in the order B-A-C with distance between B-A being 9 cm and A- C being 17 cm-and the distance between B-C being 26 cm.
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