A) 100 Hz
B) \[99\,Hz\]
C) \[96\,Hz\]
D) \[103{{\,}^{Pz}}\]
Correct Answer: B
Solution :
Frequency of two consecutive fork is 3 \[f={{f}_{1}}+(n-1)d\] Given, \[{{f}_{1}}=2{{f}_{1}},n=26,d=-3\] \[f=2f+(26-1)(-3)\] \[f=75Hz\] Frequency of \[{{18}^{\text{th}}}\] tuning fork is \[{{f}_{18}}={{f}_{1}}+(18-1)(-3)\] \[{{f}_{18}}=2\times 75+17\times (-3)\] \[150-51=99\,Hz\]
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