A) \[{{60}^{o}}\]
B) \[{{90}^{o}}\]
C) \[30{}^\circ \]
D) \[{{120}^{o}}\]
Correct Answer: B
Solution :
\[y=4\sin \frac{\pi }{4}\left( 2t+\frac{x}{8} \right)\] \[y=4\sin \left( \frac{\pi }{2}t+\frac{\pi x}{32} \right)\] ?(i) The standard equation is \[y=4\sin (\omega t\pm kx)\] ?(ii) Comparing the Eqs. (i) and (ii) we get \[k=\frac{\pi }{32}\] \[\frac{2\pi }{\lambda }=\frac{\pi }{32}\] \[\frac{\lambda }{2}=32\] \[\lambda =64\] \[\Delta \text{o }\!\!|\!\!\text{ =}\frac{2\pi }{\lambda }\] \[\Delta x=\frac{2\pi }{64}\times 16\] \[=\frac{\pi }{2}={{90}^{o}}\]
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