A) \[B{{F}_{3}}<{{H}_{2}}S<{{H}_{2}}O\]
B) \[{{H}_{2}}S<B{{F}_{3}}<{{H}_{2}}O\]
C) \[{{H}_{2}}O<{{H}_{2}}S<B{{F}_{3}}\]
D) \[{{H}_{2}}O<B{{F}_{3}}<{{H}_{2}}S\]
Correct Answer: A
Solution :
Oxygen is more electronegative than sulphur. Hence, the order of dipole moment is as \[B{{F}_{3}}<{{H}_{2}}S<{{H}_{2}}O\]
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