A) \[B>C>A\]
B) \[B>A>C\]
C) \[A>B>C\]
D) \[C>B>A\]
Correct Answer: A
Solution :
Among \[{{1}^{o}},{{2}^{o}}\] and \[{{3}^{o}}\] amines, the primary amine has the maximum strength to form the H-bond. The dipole-dipole attraction force also works between these molecules, hence the boiling point of primary amine is maximum. Between \[{{2}^{o}}\] and \[{{3}^{o}}\] amine, the tertiary amines does not from H-bond while secondary amine has some strength to form bond. \[\text{H}-\text{bond}\text{.}\] Hence, the order of boiling point is as \[\underset{\begin{smallmatrix} n-butyl\,a\min e \\ \,\,\,\,\,\,\,\,{{1}^{o}}a\min e \\ \,\,\,\,\,\,\,\,(B) \end{smallmatrix}}{\mathop{{{C}_{4}}{{H}_{9}}N{{H}_{2}}}}\,>\underset{\begin{smallmatrix} diethyl\,a\min e \\ \,\,\,\,{{2}^{o}}\,a\min e \\ \,\,\,\,\,\,\,\,\,\,\,\,\,(C) \end{smallmatrix}}{\mathop{{{({{C}_{2}}{{H}_{5}})}_{2}}NH}}\,\] \[\underset{\begin{smallmatrix} ethyl\,\dimethyl\,a\min e \\ \,\,\,\,\,\,{{3}^{o}}\,a\min e \\ \,\,\,\,\,\,(A) \end{smallmatrix}}{\mathop{>\,{{C}_{2}}{{H}_{5}}N{{(C{{H}_{3}})}_{2}}}}\,\]
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