A) \[\frac{{{\mu }_{0}}qf}{2\pi R}\]
B) \[\frac{{{\mu }_{0}}q}{2\pi fR}\]
C) \[\frac{{{\mu }_{0}}q}{2fR}\]
D) \[\frac{{{\mu }_{0}}qf}{2R}\]
Correct Answer: C
Solution :
The magnetic field at the centre of the circle \[=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2\pi i}{R}=\frac{{{\mu }_{0}}}{2}\frac{(q)}{Rt}\] We have frequency \[f=\frac{1}{T}\] \[\therefore \]The magnetic field \[B=\frac{{{\mu }_{0}}qf}{2R}\]
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