A) 2-butene
B) 1, 3-butadiene
C) n-butane
D) n-butyl chloride
Correct Answer: C
Solution :
Alkyl halide reacts with Li and \[\text{CuI}\] in the presence of ether to give lithium dialkyl cuprate which further reacts with alkyl halide to give alkane. This reaction is called Corey-House reaction. \[{{\text{C}}_{2}}{{H}_{2}}Cl+2Li\xrightarrow{\text{Ether}}{{C}_{2}}{{H}_{5}}Li+LiBr\] \[2{{C}_{2}}{{H}_{5}}Li+CuI\xrightarrow[-LiI]{}\underset{\text{lithium}\,\text{dialkyl}\,\text{cuprate}}{\mathop{Li{{({{C}_{2}}{{H}_{5}})}_{2}}Cu}}\,\] \[Li{{({{C}_{2}}{{H}_{5}})}_{2}}Cu+{{C}_{2}}{{H}_{5}}Cl\xrightarrow{{}}\]\[\underset{\text{n}-\text{butane}}{\mathop{{{C}_{2}}{{H}_{5}}-{{C}_{2}}{{H}_{5}}}}\,+{{C}_{2}}{{H}_{5}}Cu+LiCl\]
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