A) \[+\,0.76\]
B) \[-\,0.76\]
C) \[-\,0.38\]
D) \[+\,0.38\]
Correct Answer: B
Solution :
\[\because \] \[{{T}_{b}}=100.2{{\,}^{o}}C\] \[\therefore \] \[\Delta {{\Tau }_{b}}=100.2-100=0.2{{\,}^{o}}C\] \[\Delta {{\Tau }_{b}}={{K}_{b}}\times m\] \[m=\frac{\Delta {{\Tau }_{b}}}{{{K}_{b}}}=\frac{0.2}{0.5}=0.4\] \[\Delta {{\Tau }_{f}}={{K}_{f}}\times m=1.9\times 0.4\] \[=0.76\,{{\,}^{o}}C\] \[{{T}_{f}}={{T}_{o}}-\Delta {{\Tau }_{f}}=0-0.76\] \[=-0.76{{\,}^{o}}C\]
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