VMMC VMMC Medical Solved Paper-2012

  • question_answer
    For the decomposition of \[{{N}_{2}}{{O}_{5}}\]into \[{{N}_{2}}O\]and \[{{O}_{2}}\] in the presence of Ar, the velocity constant, k is                          \[k=5\times {{10}^{11}}{{e}^{-30,000/T}}\]For this, the activation energy is (in \[\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\])

    A)  2.494           

    B)  24.94       

    C)  249.42

    D)  2494

    Correct Answer: C

    Solution :

     Given, \[k=5\times {{10}^{11}}{{e}^{-30,000/T}}\] ?(i) Arrhenius equation is as \[k=A{{e}^{-{{E}_{a}}/RT}}\] From Eqs. (i) and (ii) \[-\frac{30000}{T}=\frac{{{E}_{a}}}{RT}\] \[\therefore \] \[{{E}_{a}}=30,000\times R\] \[=249420\,J\,mo{{l}^{-1}}\] \[=-249.42\,kJ\,mo{{l}^{-}}\]


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