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VMMC VMMC Medical Solved Paper-2012

  • question_answer
    The pH of 0.1 M aqueous ammonia\[({{K}_{b}}=1.8\times {{10}^{-5}})\]is

    A)  9.13            

    B)  10.13

    C)  11.13           

    D)  12.13

    Correct Answer: C

    Solution :

     The aqueous solution of ammonia is basic in nature. \[\therefore \] \[[O{{H}^{-}}]=\sqrt{{{K}_{b}}\times C}\] \[=\sqrt{1.8\times {{10}^{-5}}\times 0.1}\] \[=1.341\times {{10}^{-3}}\] \[pOH=-\log [O{{H}^{-}}]\] \[=-\log [1.341\times {{10}^{-3}}]\] \[=2.87\] \[pH=14-pOH\] \[=14-2.87=11.13\]


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