question_answer

The \[s{{p}^{3}}\]hybridisation is present on the central atom in

A)  HCHO         

B) \[BC{{l}_{3}}\]

C) \[PC{{l}_{3}}\]           

D) \[S{{O}_{3}}\]

Correct Answer: C

Solution :

 For \[s{{p}^{3}}\]hybridisation, the number of hybridised orbitals of central atom should be four. Number of hybridised orbitals = number of a bonds + number of lone pairs Number of hybridised orbitals in HCHO is 3. \[H\overset{\sigma }{\mathop{\_}}\,\overset{H}{\mathop{\overset{|\sigma }{\mathop{C}}\,}}\,\overset{\sigma }{\mathop{=}}\,O\]i.e., \[3+0=3\] Number of hybridised orbitals in \[BC{{l}_{3}}\]are 3. \[Cl\overset{\sigma }{\mathop{\_}}\,\underset{Cl}{\mathop{\underset{|\sigma }{\mathop{B}}\,}}\,\overset{\sigma }{\mathop{\_}}\,Cl\]i.e, \[3+0=3\] Number of hybridised orbitals in \[PC{{l}_{3}}\] are 4. \[Cl\underset{\sigma }{\mathop{-}}\,\underset{Cl}{\mathop{\underset{|\sigma }{\overset{\centerdot \centerdot }{\mathop{P}}}\,}}\,\underset{\sigma }{\mathop{-}}\,Cl\]i. e, \[3+1=4\] Number of hybridised orbitals in \[S{{O}_{3}}\]are 3. i.e, \[3+0=3\] Therefore, the hybridisation on central atom in \[PC{{l}_{3}}\]is \[s{{p}^{3}}.\]