A) 2.6
B) 0.24
C) 0.8
D) 2.4
Correct Answer: A
Solution :
\[\underset{1-0.8}{\mathop{\underset{1}{\mathop{BaC{{l}_{2}}(s)}}\,}}\,\xrightarrow{{{H}_{2}}O}\underset{0.8}{\mathop{\underset{0}{\mathop{B{{a}^{2+}}}}\,}}\,+\underset{\text{2}\,\text{ }\!\!\times\!\!\text{ }\,\text{0}\text{.8}\,\text{In}\,\text{aq}\text{.solution}}{\mathop{\underset{0}{\mathop{2C{{l}^{-}}}}\,}}\,\] \[i=\frac{\text{No}\text{.}\,\text{of}\,\text{moles}\,\text{after}\,\text{reaction}}{\text{Initial}\,\text{number}\,\text{ofmoles}}\] \[=\frac{1-0.8+0.8+(2\times 0.8)}{1}\] \[=2.6\]
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