question_answer

Fundamental frequency of an open pipe is\[{{f}_{0}}\] Fundamental frequency when it is half filled with water is

A) \[{{f}_{0}}\]

B)  \[{{f}_{0}}/2\]

C)  \[2{{f}_{0}}\]

D)  \[3f\]

Correct Answer: A

Solution :

 If an open pipe is half submerged in water, it     will become a closed  organ pipe of length half  that of open pipe as  shown in figure. So, its Frequency will become, \[{{f}_{c}}=\frac{v}{4\left( \frac{L}{2} \right)}=\frac{v}{2L}={{f}_{o}}\] i.e., equal to that of open pipe i.e., frequency will remain unchanged.