VMMC VMMC Medical Solved Paper-2012

  • question_answer
    At what height h above earth, the value of g becomes g/2? (R = Radius of earth)

    A)  \[3R\]

    B)  \[\sqrt{2}R\]

    C)  \[(\sqrt{2}-1)R\]

    D)  \[\frac{1}{\sqrt{2}}R\]

    Correct Answer: C

    Solution :

    The value of acceleration due to gravity at height h (when h is not negligible as compared to R) \[g=g\frac{{{R}^{2}}}{{{(R+h)}^{2}}}\] Here, \[g=\frac{g}{2}\] \[\therefore \] \[\frac{g}{2}=g\frac{{{R}^{2}}}{{{(R+h)}^{2}}}\] or \[\frac{1}{2}=\frac{{{R}^{2}}}{{{(R+h)}^{2}}}\] or \[\sqrt{\frac{1}{2}}=\frac{R}{R+h}\] or \[R+h=\sqrt{2}R\] \[\therefore \] \[h=(\sqrt{2}-1)R\]


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