VMMC VMMC Medical Solved Paper-2012

  • question_answer
    What is the refractive index of a prism whose angle \[A={{60}^{o}}\]and angle of minimum deviation \[{{d}_{m}}={{30}^{o}}\]?

    A) \[\sqrt{2}\]

    B)  \[\frac{1}{\sqrt{2}}\]

    C)  1

    D)  \[\frac{1}{\sqrt{3}}\]

    Correct Answer: A

    Solution :

     Refractive index of prism \[\mu =\frac{\sin \frac{A+{{\delta }_{m}}}{2}}{\sin A/2}\] \[=\frac{\sin \frac{{{60}^{o}}+{{30}^{o}}}{2}}{\sin \frac{{{60}^{o}}}{2}}\] \[=\frac{\sin {{45}^{o}}}{\sin {{30}^{o}}}=\frac{1/\sqrt{2}}{1/2}\] \[=\frac{1}{\sqrt{2}}\times \frac{2}{1}=\sqrt{2}\]


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