A) 8 V
B) 10 V
C) 2 V
D) 4 V
Correct Answer: B
Solution :
Electric power, \[P={{i}^{2}}R\] \[\therefore \]Current, \[i=\sqrt{\frac{P}{R}}\] For resistance of \[9\Omega \] \[{{i}_{1}}=\sqrt{\frac{36}{9}}=\sqrt{4}=2A\] \[{{i}_{2}}=\frac{{{i}_{1}}\times R}{6}=\frac{2\times 9}{6}=3A\] \[i={{i}_{1}}+{{i}_{2}}=2+3=5A\] \[{{V}_{2}}=iR=5\times 2=10V\]
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