2. Solved Papers
  3. VMMC

VMMC VMMC Medical Solved Paper-2012

  • question_answer
    The decay constant of a radio isotope is \[\lambda .\] If \[{{A}_{1}}\]and \[{{A}_{2}}\]are its activities at times \[{{t}_{1}}\]and \[{{t}_{2}}\]respectively, the number of nuclei which have decayed during the time \[({{t}_{1}}-{{t}_{2}})\]

    A) \[{{A}_{1}}{{t}_{1}}-{{A}_{2}}{{t}_{2}}\]

    B)  \[{{A}_{1}}-{{A}_{2}}\]

    C)  \[\frac{({{A}_{1}}-{{A}_{2}})}{\lambda }\]

    D)  \[\lambda ({{A}_{1}}-{{A}_{2}})\]

    Correct Answer: C

    Solution :

     \[{{A}_{1}}=\lambda {{N}_{1}}\] \[{{A}_{2}}=\lambda {{N}_{2}}\] \[{{N}_{1}}-{{N}_{2}}=\left[ \frac{{{A}_{1}}-{{A}_{2}}}{\lambda } \right]\]


You need to login to perform this action.
You will be redirected in 3 sec spinner