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VMMC VMMC Medical Solved Paper-2012

  • question_answer
    A conducting circular loop is placed in a uniform magnetic field, B = 0.025 T with its plane perpendicular to the loop. The radius of  the loop is made to shrink at a constant rate of \[\text{1}\,\text{mm}{{\text{s}}^{-1}}.\] The induced emfwhen the radius is 2 cm, is

    A) \[2\pi \mu \,V\]

    B)  \[\pi \mu \,V\]

    C)  \[\frac{\pi }{2}\mu V\]

    D)  \[2\mu V\]

    Correct Answer: B

    Solution :

     Magnetic flux \[\text{o}|=\,B.A\] \[=B.\pi {{r}^{2}}\] Induced emf, \[|e|=\frac{d\text{o }\!\!|\!\!\text{ }}{dt}=B\pi 2r\frac{dr}{dt}\] \[=0.025\times \pi \times 2\times 2\times {{10}^{-2}}\times 1\times {{10}^{-3}}\] \[=\pi \mu V\]


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