VMMC VMMC Medical Solved Paper-2012

  • question_answer
    A particle moves a distance \[x\] in time t according to equation \[x={{(t+5)}^{-1}}.\]The acceleration of particle is proportional to

    A) \[{{(\text{velocity})}^{3/2}}\]     

    B) \[{{(distance)}^{2}}\]

    C) \[{{(distance)}^{-2}}\]     

    D)  \[{{(velocity)}^{2/3}}\]

    Correct Answer: A

    Solution :

     Given, distance \[x={{(t+5)}^{-1}}\] ?(i) Differentiating Eq. (i) w.r.t. t, we get \[\frac{dx}{dt}=(v)=\frac{-1}{{{(t+5)}^{2}}}\] ?(ii) Again, differentiating Eq. (i) w.r.t. t, we get \[\frac{{{d}^{2}}x}{d{{t}^{2}}}=(a)=\frac{2}{{{(t+5)}^{3}}}\] ?(iii) Comparing Eqs. (ii) and (iii), we get \[a\propto {{(v)}^{3/2}}\]


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