question_answer

In the following reaction  \[\text{X}\xrightarrow{\text{Bromination}}Y\xrightarrow[\text{+HCl}]{\text{NaN}{{\text{O}}_{\text{2}}}}Z\xrightarrow[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH}]{\text{Boiling}}\] tribromo benzenei, X is

A) benzoic acid                      

B) salicylic acid       

C)         phenol  

D)        aniline

Correct Answer: D

Solution :