A) \[HI{{O}_{3}},\text{ }{{H}_{2}}S{{O}_{4}},\text{ }{{H}_{3}}P{{O}_{4}}\] and \[\text{ }C{{O}_{2}}\]
B) \[HI{{O}_{3}},\text{ }{{H}_{2}}S{{O}_{4}},\text{ }{{H}_{3}}P{{O}_{3}}\] and\[\text{ }C{{O}_{2}}\]
C) \[HI{{O}_{2}},\text{ }{{H}_{2}}S{{O}_{4}},\text{ }{{H}_{3}}P{{O}_{4}}\] and CO
D) \[{{I}_{2}}{{O}_{5}},S{{O}_{2}},{{P}_{2}}O\]and \[C{{O}_{2}}\]
Correct Answer: A
Solution :
\[\text{HN}{{\text{O}}_{\text{3}}}\]reacts with the given elements in the following manner. \[{{\text{I}}_{2}}+10HN{{O}_{3}}\xrightarrow{\Delta }2HI{{O}_{3}}+10N{{O}_{2}}+4{{H}_{2}}O\] \[S+6HN{{O}_{3}}\xrightarrow{\Delta }{{H}_{2}}S{{O}_{4}}+6N{{O}_{2}}+2{{H}_{2}}O\] \[{{P}_{4}}+20HN{{O}_{3}}\xrightarrow{\Delta }4{{H}_{3}}P{{O}_{4}}+20N{{O}_{2}}+4{{H}_{2}}O\] \[C+4HN{{O}_{3}}\xrightarrow{\Delta }C{{O}_{2}}+4N{{O}_{2}}+2{{H}_{2}}O\]
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