A) increases cell emf
B) increases the current flow
C) decreases the cell emf
D) alter the pH of the solution
Correct Answer: C
Solution :
\[2F{{e}^{3+}}+Zn\xrightarrow{{}}Z{{n}^{2+}}+2F{{e}^{2+}}\] \[2F{{e}^{3+}}+2{{e}^{-}}\xrightarrow{{}}2F{{e}^{2+}}\] According to Nemsts equation, \[{{E}_{cell}}\,=E_{cell}^{o}\,-\frac{RT}{nF}\,\ln \,\frac{{{[F{{e}^{2+}}]}^{2}}}{{{[F{{e}^{3+}}]}^{2}}}\] Thus, \[{{\text{E}}_{\text{cell}}}\] decreases as the \[[F{{e}^{2+}}]\] increases or \[[F{{e}^{3+}}]\] decreases.
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