A) Plancks constant
B) gravitational constant
C) dielectric constant
D) None of the above
Correct Answer: D
Solution :
Dimensional formula of \[{{(velcity)}^{2}}+\] radius \[=\frac{{{[{{M}^{0}}L{{T}^{-1}}]}^{2}}}{[{{M}^{0}}LT]}\] \[=[{{M}^{0}}L{{T}^{-2}}]\] \[\text{= acceleration}\]
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