VMMC VMMC Medical Solved Paper-2011

  • question_answer
    A car moving with a speed of 25 m/s takes a U-tum in 5 s, without changing its speed. The average acceleration during these 5 s is

    A)  \[10\,m/{{s}^{2}}\]

    B)  \[5\,m/{{s}^{2}}\]                

    C)  \[2\,m/{{s}^{2}}\]          

    D)         \[7\,m/{{s}^{2}}\]

    Correct Answer: A

    Solution :

                            Average acceleration \[\text{= }\frac{\text{change in velocity}}{\text{time}}\] \[=\frac{25-(-25)}{5}\] \[=10\,m/{{s}^{2}}\]


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