A) 5\[\mu C\]
B) 10\[\mu C\]
C) 12\[\mu C\]
D) 15\[\mu C\]
Correct Answer: B
Solution :
\[{{C}_{1}}=2\mu F,{{C}_{2}}=3\mu F,{{C}_{3}}=6\mu F\]and \[V=10\]Volt Total capacity (in series) \[\frac{1}{C}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{{{C}_{3}}}\] \[=\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\] \[=\frac{3+2+1}{6}\] \[C=1\,\mu F\] Total energy q = CV \[=1\times 10\] \[=10\,\mu C\]
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