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VMMC VMMC Medical Solved Paper-2011

  • question_answer
    A source and listener are both moving towards each other with speed v/10, where v is the speed of sound. If the frequency of the note emitted by the source is f the frequency heard by the listener would be nearly

    A)  1.11\[f\]                             

    B)  1.22 \[f\]            

    C)        \[f\]                      

    D)         1.27 \[f\]

    Correct Answer: B

    Solution :

                            Source and observer both are moving. So, apparent frequency \[n=n\left[ \frac{v+{{v}_{o}}}{v-{{v}_{s}}} \right]\] where, \[{{v}_{o}}=\]speed of observer \[{{v}_{s}}=\] speed of source \[f=f\left[ \frac{v+v/10}{v-v/10} \right]\] \[v=\] speed of sound \[f=f\frac{11}{9}\] \[=1.22\,f\]


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