VMMC VMMC Medical Solved Paper-2011

  • question_answer
    The upper end of hanging wire of radius 4 mm and length 100 cm is clamped rigidly. Its lower end is twisted through an angle \[30{}^\circ \]. The angle of shear is

    A) \[12{}^\circ \]

    B)        \[0.12{}^\circ \]

    C) \[1.2{}^\circ \]

    D)         \[0.012{}^\circ \]

    Correct Answer: B

    Solution :

                            Angle of shear \[(\theta )=\frac{x\text{o }\!\!|\!\!\text{ }}{l}\] \[x=4\,mm\,=4\times {{10}^{-1}}\,cm\] \[l=100\,cm,\,\]and \[\text{o }\!\!|\!\!\text{ =}\,\text{3}{{\text{0}}^{o}}\] \[\theta =\frac{4\times {{10}^{-1}}\times {{30}^{o}}}{100}={{0.12}^{o}}\]


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