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VMMC VMMC Medical Solved Paper-2011

  • question_answer
    The thermo emf E (in volts) of a certain thermocouple is found to vary with 9 (in \[{}^\circ C\]) according to equation \[E=20\,\theta -{{\theta }^{2}}/20,\] where \[\theta \] is temperature of the hot junction, the cold junction being kept at \[0{}^\circ C\]. Then the neutral temperature of the thermocouple is

    A) \[300{}^\circ C\]              

    B)                        \[400{}^\circ C\]

    C) \[100{}^\circ C\]

    D)        \[200{}^\circ C\]

    Correct Answer: D

    Solution :

                            \[E=20\,\theta -{{\theta }^{2}}/20\] When \[\theta ={{\theta }_{n}}.dE/d\theta =0\] \[\therefore \]  \[dE/d\theta =20-2{{\theta }_{n}}/20=0\] or            \[{{\theta }_{n}}=200{{\,}^{o}}C\]


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