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VMMC VMMC Medical Solved Paper-2011

  • question_answer
    A 5 g droplet of liquid nitrogen is enclosed in a 50 mL tube which is sealed at very low pressure. When the tube is warmed to 35°C the nitrogen pressure in the tube is (molecular weight of nitrogen = 28 and R = 8.3 J/mol K)

    A)  \[1.01\,\times {{10}^{5}}\,N/{{m}^{2}}\]

    B)  \[9.13\,\times {{10}^{4}}\,N/{{m}^{2}}\]

    C)  \[9.13\,\times {{10}^{3}}\,N/{{m}^{2}}\]

    D)                                     \[18.26N/{{m}^{2}}\]

    Correct Answer: C

    Solution :

                            \[pV=\frac{m}{M}RT\] \[\Rightarrow \]               \[p=\frac{m}{M}\frac{RT}{M}\] \[p=\frac{5\times {{10}^{-3}}}{28}\times \frac{8.3\times (273+35)}{50\times {{10}^{-6}}}\] \[=9.13\times {{10}^{3}}N/{{m}^{2}}\]


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