VMMC VMMC Medical Solved Paper-2011

  • question_answer
    The wavelength difference of light waves of wave numbers \[2\times {{10}^{6}}\,/m\] and \[2.25\times {{10}^{6}}/m\] is

    A)  \[0.556\,\times {{10}^{-6}}\,m\]

    B)  \[0.0556\,\times {{10}^{6}}\,m\]                             

    C)  \[0.0556\,\times {{10}^{-6}}\,m\]           

    D)         \[0.556\,\times {{10}^{6}}\,m\]

    Correct Answer: C

    Solution :

                            \[\lambda =\frac{1}{2\times {{10}^{6}}}-\frac{1}{2.25\times {{10}^{6}}}\] \[=\frac{2.25-2}{2\times 2.25\times {{10}^{6}}}\] \[=\frac{0.25}{2\times 2.25\times {{10}^{6}}}\] \[=0.0556\times {{10}^{-6}}m\]


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