A) \[{{\text{O}}_{\text{2}}}\] and \[~Xe\] have comparable electronegativities
B) \[{{\text{O}}_{\text{2}}}\] and \[~Xe\]have comparable ionization enthalpies
C) Both \[{{\text{O}}_{\text{2}}}\] and \[~Xe\]are gases
D) None of the above
Correct Answer: B
Solution :
The formation of \[O_{2}^{+}{{[Pt{{F}_{6}}]}^{-}}\] is the basis for the formation of xenon fluoride because the first ionization enthalpy of xenon gas \[(1170\,kJ\,mo{{l}^{-1}})\] is fairly close to that of oxygen \[(1175\,kJ\,mo{{l}^{-1}}).\]
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