A) \[v\frac{R}{r}\]
B) \[v\frac{{{R}^{2}}}{{{r}^{2}}}\]
C) v
D) 2v
Correct Answer: B
Solution :
Terminal velocity \[v=\frac{2}{9}\frac{{{r}^{2}}(\rho -\sigma )g}{\eta }\] \[\therefore \] \[v\propto {{r}^{2}}\] \[\frac{v}{V}=\frac{{{r}^{2}}}{{{R}^{2}}}\] \[V=\frac{v{{R}^{2}}}{{{r}^{2}}}\]You need to login to perform this action.
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