A) 7.6 cm
B) 4.8 cm
C) 1.2 cm
D) 0.6 cm
Correct Answer: D
Solution :
\[l\propto \frac{1}{{{r}^{2}}}\](F, L and Y are constant) \[\therefore \] \[\frac{{{l}_{2}}}{{{l}_{1}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}={{\left( \frac{1}{2} \right)}^{2}}\] \[{{l}_{2}}=\frac{{{l}_{1}}}{4}=\frac{2.4}{4}\] \[{{l}_{2}}=0.6\,cm\]
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