A) mg
B) \[m(g+\pi n{{r}^{2}})\]
C) m (g + nr)
D) \[m\left\{ g+\frac{{{\pi }^{2}}{{n}^{2}}r}{900} \right\}\]
Correct Answer: D
Solution :
\[{{T}_{net}}=\frac{m{{v}^{2}}}{r}+mg=mr{{\omega }^{2}}+mg\] \[=mr{{\left( \frac{2\pi n}{60} \right)}^{2}}+mg=m\left[ \frac{{{\pi }^{2}}{{n}^{2}}r}{900}+g \right]\]You need to login to perform this action.
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