A) \[-271\,kJ\]
B) \[1.403\,J\]
C) \[-\text{ }135\text{ }kJ\]
D) \[-\text{ }115\text{ }kJ\]
Correct Answer: A
Solution :
\[2{{e}^{-}}+2VO_{2}^{+}+4{{H}^{+}}\xrightarrow{{}}2V{{O}^{2+}}+2{{H}_{2}}O;\] \[*\,\,\Delta {{E}^{o}}=1.0\,V\] ?(i) \[Cd\xrightarrow{{}}C{{d}^{2+}}2{{e}^{-}};\] \[^{*}\Delta {{E}^{o}}=+\,0.40\,V\]?(ii) On adding Eq (i) and (ii), we get \[2VO_{2}^{+}+4{{H}^{+}}+Cd\to 2V{{O}^{2+}}+2{{H}_{2}}O+C{{d}^{2+}};\] \[E_{cell}^{o}=1.0+0.40=1.40\,V\] \[\Delta {{G}^{o}}=-nFE_{cell}^{o}=-2\times 96500\times 1.4\] \[=-270200\,J=-271\,kJ\] * Since in this \[\text{Q}\text{.}{{\text{E}}^{\text{o}}}\]values are not given, it is incorrect. These values are taken from reference books.
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