A) Acetamide
B) Propionamide
C) Formamide
D) Methyl cyanide
Correct Answer: B
Solution :
Propionamide, when reacts with bromine and caustic potash, gives ethylamine. This reaction is called Hofmann bromamide reaction. \[\underset{\text{propionamide}}{\mathop{C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}}}\,+B{{r}_{2}}+NaOH\xrightarrow{{}}\] \[\underset{\text{ethyl}\,\text{amine}}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,+{{K}_{2}}C{{O}_{3}}+KBr+{{H}_{2}}O\]
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