A) \[C{{H}_{3}}CHO\]
B) \[C{{H}_{3}}C{{H}_{2}}CHO\]
C) \[{{(C{{H}_{3}})}_{3}}CCHO\]
D) \[{{(C{{H}_{3}})}_{2}}CHCHO\]
Correct Answer: C
Solution :
The given reaction is Cannizaro reaction. It is given by only those aldehydes in which \[\alpha -H\]atom is not present. Hence, \[{{\text{(C}{{\text{H}}_{\text{3}}}\text{)}}_{\text{3}}}\text{C}\text{.CHO}\]due to the absence of \[\alpha -H\]atom gives the Cannizaro reaction as \[2{{(C{{H}_{3}})}_{3}}C.CHO\xrightarrow{\text{Conc}\text{.}\,\text{NaOH}}{{(C{{H}_{3}})}_{3}}C.C{{H}_{2}}OH\] \[+{{(C{{H}_{3}})}_{3}}C.COONa\] \[{{\text{(C}{{\text{H}}_{\text{3}}}\text{)}}_{\text{2}}}\text{CHCHO}\]also give Cannizaro reaction, however in if \[\alpha -H\]atom is present
You need to login to perform this action.
You will be redirected in
3 sec
