A) n-hexane
B) n-pentane
C) 2-methyl butane
D) 2, 2-dimethyl propane
Correct Answer: A
Solution :
Boiling point of alkanes \[\propto \] molecular mass with branching surface area, and hence, van der Waals forces decrease, hence, straight chain alkanes have higher boiling point than their corresponding branched chain isomer. Hence, n-hexane, having highest molecular mass among the given has the highest boiling point.
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