VMMC VMMC Medical Solved Paper-2009

  • question_answer
    The molar concentration of 32 g of oxygen in 10 L is

    A) \[3.2\,mol\,{{L}^{-1}}\] 

    B)  \[3.2\,\,g\,{{L}^{-1}}\]  

    C) \[1.00\,mol\,{{L}^{-1}}\]              

    D) \[0.10\,mol\,{{L}^{-1}}\]

    Correct Answer: D

    Solution :

    Molar concentration (molarity) \[\text{= }\frac{\text{moles of solute}}{\text{volume of soution}}\] \[=\frac{32}{32\times 10}mol/L\] \[=0.10\,mol\,{{L}^{-1}}\]


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