A) \[T{{i}^{2+}}\]
B) \[N{{i}^{2+}}\]
C) \[P{{t}^{2+}}\]
D) \[Z{{r}^{2+}}\]
Correct Answer: B
Solution :
On moving along a period, ionic radii decreases while on moving down a group, ionic radii increases. Since, \[T{{i}^{2+}}\]and \[Z{{n}^{2+}}\]belong to IV B group and \[N{{i}^{2+}}\]and \[P{{t}^{2+}}\]belong to VIII group, ionic radii of \[T{{i}^{2+}}<Z{{r}^{2+}},\]and \[N{{i}^{2+}}<P{{t}^{2+}}\] Further \[\text{T}{{\text{i}}^{\text{2+}}}\]and \[\text{N}{{\text{i}}^{\text{2+}}}\]belong to same period, hence, \[\text{N}{{\text{i}}^{\text{2+}}}\]has the smallest radii among the given.
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