VMMC VMMC Medical Solved Paper-2009

  • question_answer
    Three masses of 2 kg, 4 kg and 4 kg are placed at the three points (1, 0, 0), (1, 1, 0) and (0, 1, 0) respectively. The position vector of its centre of mass is

    A) \[\frac{3}{5}\mathbf{\hat{i}}+\frac{4}{5}\mathbf{\hat{j}}\]

    B)                                                        \[(3\mathbf{\hat{i}}+\mathbf{\hat{j}})\]                            

    C)                        \[\frac{2}{5}\mathbf{\hat{i}}+\frac{4}{5}\mathbf{\hat{j}}\]                        

    D)                        \[\frac{1}{5}\mathbf{\hat{i}}+\frac{3}{5}\mathbf{\hat{j}}\]

    Correct Answer: A

    Solution :

    \[{{\vec{v}}_{CM}}=\frac{{{m}_{1}}{{{\vec{v}}}_{1}}+{{m}_{2}}{{{\vec{v}}}_{2}}}{{{m}_{1}}+{{m}_{2}}}\] \[=\frac{2\times (1\hat{i})+4(1\hat{i}+1\hat{j})+4(1\hat{j})}{2+4+4}=\frac{3}{5}\hat{i}+\frac{4}{5}\hat{j}\]


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