2. Solved Papers
  3. VMMC

VMMC VMMC Medical Solved Paper-2009

  • question_answer
    A motor cycle racer takes a round with speed \[20\,m{{s}^{-1}}\] in a curvature of radius of R = 40 m, then the leaning angle of motor cycle for safe turn is \[(g=10\,m{{s}^{-2}})\])

    A) \[20{}^\circ \]   

    B)                                                         \[30{}^\circ \]                  

    C)                        \[45{}^\circ \]                                   

    D)                         \[60{}^\circ \]

    Correct Answer: C

    Solution :

    A motor cyclist provides himself the necessary centripetal force by leaning inward on a horizontal track, while going round a curve. For a safe turn cyclist should bend through an angle \[\theta ={{\tan }^{-1}}\left[ \frac{{{v}^{2}}}{rg} \right]={{\tan }^{-1}}\left[ \frac{{{(20)}^{2}}}{40\times 10} \right]\]                 \[={{\tan }^{-1}}(1)={{45}^{o}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner